How much hydrogen will be released when 1.2 g of magnesium reacts with chloride acid?

univerkov | January 17, 2021 | education

Given:
m (Mg)
To find:
V (H2)
Decision:
Mg + 2HCl = H2 + MgCl2
n (Mg) = m / M = 1.2 g / 24 g / mol = 0.05 mol
n (Mg): n (H2) = 0.05 mol
V (H2) = n * Vm = 0.05 mol * 22.4 L / mol = 1.12 L
Answer: 1.12 L

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