How much hydrogen will be released when 1 kg of zinc is dissolved in an excess of acid?

The reaction between zinc and sulfuric acid is described by the following chemical reaction equation.
Zn + H2SO4 = ZnSO4 + H2;
1 mole of metal reacts with 1 mole of acid. In this case, 1 mol of salt is synthesized and 1 mol of gaseous hydrogen is released.
Regardless of the type of acid, dissolving 1 mole of zinc releases one mole of hydrogen.
Let’s calculate the chemical amount of a substance in 32.5 grams of zinc.
M Zn = 65 grams / mol;
N Zn = 1000/65 = 15.3846 mol;
The same chemical amount of hydrogen will be obtained.
Let’s calculate its volume.
One liter of ideal gas under normal conditions assumes a volume of 22.4 liters
V H2 = 15.3846 x 22.4 = 344.6 liters