How much hydrogen will be released when 11.5 grams of sodium reacts with water?

Sodium with water reacts violently with the formation of alkali – sodium hydroxide and with the release of hydrogen gas.

2 Na + H2O = 2 NaOH + H2

Molar mass of sodium = 23 g / mol, molar volume of hydrogen = 22.4 L / mol

Let’s make a proportion according to the reaction equation:

11.5 g sodium corresponds to X l. hydrogen like

2 * 23 g / mol sodium corresponds to 22.4 l / mol hydrogen

X = (11.5 * 22.4) / (2 * 23) = 5.6 liters.

Answer: 5.6 liters of hydrogen