How much hydrogen will be released when 130 g of zinc interacts with water?

We write down the reaction equation.

Zn + 2H2O = Zn (OH) 2 + H2.

Determine the amount of zinc. To do this, you must first calculate the molar mass of zinc.

M (Zn) = 65 g / mol.

n (Zn) = 130/65 = 2 mol.

Next, we determine the amount of hydrogen substance and calculate the volume of hydrogen.

2 mol – x mol.

1 mol – 1 mol.

X = 2 mol.

V = 2 * 22.4 = 44.8 liters.

Answer: the volume is 44.8 liters.



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