How much hydrogen will be released when 220 grams of 30% acid interacts with potassium?

Given:
m solution (HCl) = 220 g
ω (HCl) = 30%

To find:
V (H2) -?

Decision:
1) Take hydrochloric acid (HCl) as an acid;
2) Write the reaction equation:
2K + 2HCl => 2KCl + H2 ↑;
3) Calculate the molar mass of HCl:
M (HCl) = Mr (HCl) = Ar (H) + Ar (Cl) = 1 + 35.5 = 36.5 g / mol;
4) Calculate the mass of HCl:
m (HCl) = ω (HCl) * m solution (HCl) / 100% = 30% * 220/100% = 66 g;
5) Calculate the amount of HCl substance:
n (HCl) = m (HCl) / M (HCl) = 66 / 36.5 = 1.8 mol;
6) Determine the amount of substance H2:
n (H2) = n (HCl) / 2 = 0.9 mol;
7) Calculate the volume H2:
V (H2) = n (H2) * Vm = 0.9 * 22.4 = 20.16 liters.

Answer: The volume of H2 is 20.16 liters.