How much hydrogen will be released when 230 g of zinc react with hydrochloric acid?

univerkov | September 3, 2021 | education

1. Between zinc and hydrochloric acid, a reaction proceeds:

Zn + 2HCl = ZnCl2 + H2 ↑;

2.Calculate the chemical amount of zinc:

n (Zn) = m (Zn): M (Zn) = 230: 65 = 3.5385 mol;

3. Determine the amount of hydrogen:

n (H2) = n (Zn) = 3.5385 mol;

4. find the volume of evolved hydrogen:

V (H2) = n (H2) * Vm = 3.5385 * 22.4 = 79.26 liters.

Answer: 79.26 liters.

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