How much hydrogen will be released when 3 g of zinc interact with water?

m (Zn) = 3 g.

Determine the volume of hydrogen that will result from the reaction. We write down the resulting reaction equation.

Zn + 2HOH = Zn (OH) 2 + H2.

First, we find the amount of zinc. We write down the solution.

n = m / M.

M (Zn) = 65 g / mol.

n (Zn) = 3 g / 65 g / mol = 0.09 mol.

Further, according to the reaction equation, we find the amount of hydrogen substance.

0.09 mol Zn – x mol H2

1 mol Zn – 1 mol H2

Find the unknown value of x.

X = 0.09 * 1: 1 = 0.09 mol.

Find the volume of hydrogen.

n = V / Vm.

V = n * Vm = 0.09 * 22.4 = 2.1 liters.

Answer: the volume of hydrogen is 2.1 liters.