How much hydrogen will be released when 4 g of calcium interacts with water?

The reaction of calcium with water is described by the following chemical reaction equation:

Ca + 2H2O = Ca (OH) 2 + H2;

One mole of calcium reacts with two moles of water. This forms one mole of hydroxide and one mole of hydrogen.

Let’s find the amount of the substance in 4 grams of calcium.

M Ca = 40 grams / mol;

N Ca = 4/40 = 0.1 mol;

The same amount of hydrogen will be released.

One mole of ideal gas under normal conditions takes a volume of 22.4 liters.

V H2 = 0.1 x 22.4 = 2.24 liters;