How much hydrogen will be released when 48 g of methanol interacts with calcium?

1. Let’s compose the reaction equation:

2CH3OH + Ca → (CH3O) 2Ca + H2 ↑;

2.Calculate the chemical amount of reacting calcium:

n (Ca) = m (Ca): M (Ca) = 48: 40 = 1.2 mol;

3.According to the equation, as a result of the interaction of 1 mol of calcium, 1 mol of hydrogen is formed, then the amount of hydrogen is:

n (H2) = n (Ca) = 1.2 mol;

4.Set the volume of evolved hydrogen:

V (H2) = n (H2) * Vm = 1.2 * 22.4 = 26.88 liters.

Answer: 26.88 liters.