How much hydrogen will be released when 9.2 grams of sodium interacts with ethyl alcohol?

Let’s make the equation:
2C2H5OH + 2Na = 2C2H5ONa + H2 – substitution reaction, hydrogen gas is released;
Let’s make calculations using the formulas:
M (C2H5OH) = 12 * 2 + 16 + 6 = 46 g / mol;
Y (C2H5OH) = m (C2H5OH) / M (C2H5OH); Y (C2H5OH) = 9.2 / 46 = 0.2 mol;
Let’s make a proportion according to the reaction equation:
0.2 mol (C2H5OH) – X mol (H2);
-2 mol -1 mol hence, X mol (H2) = 0.2 * 1/2 = 0.1 mol;
Let’s calculate the volume of hydrogen according to Avogadro’s law:
V (H2) = 0.1 * 22.4 = 2.24 liters.
Answer: 2.24 liters are released during the reaction. hydrogen gas.