# How much hydrogen will be released when aluminum interacts with 100 percent of a solution containing

**How much hydrogen will be released when aluminum interacts with 100 percent of a solution containing 5% hydrochloric acid.**

m (HCl) = 100 g.

W (HCl) = 5%.

Determine the amount of hydrogen released as a result of the reaction. We write down the solution.

First, we write down the equation of reactions.

2Al + 6HCl = 2AlCl3 + 3H2

We find the mass of hydrogen chloride. We use the following formula.

W = m r.v / m r-ra * 100%.

m r.v = m solution * W / 100% = 100 * 5/100 = 5 g HCl.

Find the amount of HCl substance.

n = m / M.

M (HCl) = 1 + 35.5 = 36.5 g / mol.

n = 5 / 36.5 = 0.14 mol.

Using the reaction equation, we find the amount of hydrogen substance.

0.14 mol HCl – x mol H2.

6 mol HCl – 3 mol H2.

X = 0.14 * 3: 6 = 0.07 mol H2.

Find the volume of hydrogen.

n = V / Vm.

V = n * Vm = 0.07 mol * 22.4 L / mol = 1.568 L.

Answer: the volume of hydrogen is 1.568 liters.