How much hydrogen will be released when aluminum reacts with an amount of 7 mol of substance with hydrochloric acid?

The reaction of interaction of aluminum with hydrochloric acid is described by the following chemical reaction equation.

Al + 3HCl = AlCl3 + 3/2 H2;

1 mole of aluminum reacts with three moles of hydrochloric acid. This forms 1 mol of aluminum chloride and 1.5 mol of hydrogen.

When 7 mol of metal dissolves, 7 x 1.5 = 10.5 mol of hydrogen gas will be released.

Let’s find its volume.

One mole of ideal gas takes up a volume of 22.4 liters under standard normal conditions.

The volume of hydrogen will be equal to:

V H2 = 10.5 x 22.4 = 235.2 liters;