How much hydrogen will be released when calcium interacts with H2O, if you get 14.8 g. calcium hydroxide.

The interaction of calcium with water occurs in accordance with the following chemical reaction equation:

Ca + 2H2O = Ca (OH) 2 + H2;

When 1 mole of metal interacts with 2 moles of water, 1 mole of hydrogen gas is released. In this case, 1 mol of its hydroxide is synthesized.

Let’s calculate the chemical amount of a substance in 14.8 grams of hydroxide.

N Mg = 14.8 / (40 + 2 + 16 x 2) = 14.8 / 74 = 0.2 mol;

0.2 mol of metal will react with 0.4 mol of water. This will release 0.2 mol of hydrogen.

Let’s calculate its volume.

One mole of gas under normal conditions fills a volume of 22.4 liters.

The volume of hydrogen will be:

V H2 = 0.2 x 22.4 = 4.48 liters;