How much hydrogen will be released when interacting with hydrochloric acid 0.1 mol of aluminum?

Aluminum reacts with hydrochloric acid. In this case, an aluminum chloride salt can be obtained and hydrogen gas bubbles are released. The reaction is described by the following equation.

Al + 3HCl = AlCl3 + 3/2 H2;

N Al = 0.1 mol;

The chemical amount of released hydrogen will be: 0.1 x 3/2 = 0.15 mol

Let’s define its volume.

To this end, we multiply the chemical amount of the substance by the volume of 1 mole of gas (filling a space with a volume of 22.4 liters).

V H2 = 0.15 x 22.4 = 3.36 liters;