How much hydrogen will be released when zinc is exposed to hydrochloric acid containing 10.95 g of hydrogen chloride?

Let’s write the reaction equation:
Zn + 2HCl = ZnCl2 + H2
It can be seen from the reaction equation that:
ν (H2) / ν (HCl) = 1/2
2 * ν (H2) = ν (HCl)
2 * V (H2) / Vm (H2) = m (HCl) / M (HCl)
Determine the molar mass M (HCl):
M (HCl) = 1 + 35 = 36 g / mol
Determine the volume of hydrogen:
V (H2) = m (HCl) * Vm (H2) / (2 * M (HCl)) = 10.95 * 22.4 / (2 * 36) = 3.26 liters.
Answer: 3.26 liters. hydrogen.