How much hydrogen will be released when zinc reacts with 365 grams of 10% hydrochloric acid solution?

univerkov | December 9, 2020 | education

Zn + 2HCL = ZnCl2 + H2
1) m (substance) = m (solution) * w
m (HCl) = (365 * 10%) / 100 = 36.5 (g)
M (HCl) = 35.5 + 1 = 36.5 g / mol
2) n (HCl) = m / M
n (HCl) = 36.5 / 36.5 = 1 (mol)
3) n (H2) = 1 / 2n (HCl)
n (H2) = 1/2 = 0.5 mol
4) V (H2) = Vm * n
V = 0.5 * 22.4 = 11.2 liters
Answer: 11.2 l

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