How much information is transmitted in 0 minutes 13 seconds at a data transfer rate of 8192 baud?

How much information is transmitted in 0 minutes 13 seconds at a data transfer rate of 8192 baud? At what speed is the transfer of information in the volume of 1715 Kb, if the transfer lasts 5 minutes 43 seconds? How long does it take to transfer 2990 bytes of information at an effective data rate of 26 bps?

1. One baud has 4 bits / s.
This means that 8192 baud = 2048 bits per second.
Let’s multiply the baud rate by the given time:
2048 * 13 = 26624 bits.
2.5 minutes 43 seconds = 343 seconds.
Divide the file size by the time it took to transfer:
1715/343 = 5 kilobytes per second = 40 kilobytes per second.
3. Divide the file size by the speed at which it was transferred:
2990/26 = 115 seconds.