How much iron do you need to take to get 116g of iron scale Fe3O4? How much oxygen will be consumed in this reaction?

| June 14, 2021 | education

Let’s find the amount of the substance of the iron scale Fe3O4.

n = m: M.

M (Fe3O4) = 56 × 3 + 16 × 4 = 232 g / mol.

n = 116 g: 232 g / mol = 0.5 mol.

Let’s compose the reaction equation, find the quantitative ratios of substances.

3Fe + 2O2 = Fe3O4

For 1 mole of iron scale, there are 3 moles of iron. The substances are in quantitative ratios of 1: 3. The amount of the iron substance will be 3 times more than the amount of the iron scale substance.

n (Fe) = 3n (Fe3O4) = 0.5 mol × 3 = 1.5 mol.

Let’s find the mass of iron.

m = n M.

M (Fe) = 56 g / mol.

m = 1.5 mol × 56 g / mol = 84 g.

Let’s find the mass of oxygen.

For 1 mole of iron scale, there are 2 moles of oxygen. Substances are in quantitative ratios 1: 2. The amount of oxygen substance will be 2 times more than the amount of iron scale substance.

n (Fe) = 3n (Fe3O4) = 0.5 mol × 2 = 1 mol.

M (O2) = 32 g / mol.

m = 1 mol × 32 g / mol = 32 g.

Answer:; m (O2) = 32 g; m (Fe) = 84 g.



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