How much iron oxide ||| is formed by thermal decomposition of iron hydroxide (|||) weighing 2.7 g?

Let’s write down the solution according to the condition of the problem:
m = 2.7 g. X g. -?
1.2Fe (OH) 3 = Fe2O3 + 3H2O – decomposition reaction, iron oxide (3) was obtained;
2. Calculations by formulas:
M Fe (OH) 3 = 106.8 g / mol;
M (Fe2O3) = 159.6 g / mol.
3. For the initial substance, we determine the number of moles, if the mass is known:
Y Fe (OH) 3 = m / M = 2.7 / 106.8 = 0.025 mol.
4. Proportion:
0.025 mol Fe (OH) 3 – X mol (Fe2O3);
-2 mol – 1 mol from here, X mol (Fe2O3) = 0.025 * 1/2 = 0.01 mol.
5. Find the mass of the product:
m (Fe2O3) = Y * M = 0.01 * 159.6 = 1.6 g.
Answer: the mass of iron oxide (3) is 1.6 g.