How much iron reacts with sulfur if 22 g of iron sulfide is formed?

Let’s implement the solution:
1. We compose the equation according to the condition of the problem:
Y mole -? m = 22 g;
Fe + S = FeS – compounds, iron sulfide was formed;
2. We make calculations by the formulas:
M (Fe) = 55.8 g / mol.
M (FeS) = 87.8 g / mol.
3. Determine the number of moles of the product:
Y (FeS) = m / M = 22 / 87.8 = 0.25 mol.
Y (Fe) = 0.25 mol since the amount of substances according to the equation is 1 mol.
Answer: 0.25 mol of iron is required to carry out the process.