How much iron will 3.36 liters of chlorine react with? Determine the composition and amount

How much iron will 3.36 liters of chlorine react with? Determine the composition and amount of the salt substance formed as a result of the reaction. Can you also write the reaction itself?

Given:
V (Cl2) = 3.36 L

To find:
n (Fe) -?
m (Fe) -?
n (salt) -?
salt composition -?

Decision:
1) 2Fe + 3Cl2 => 2FeCl3;
2) n (Cl2) = V (Cl2) / Vm = 3.36 / 22.4 = 0.15 mol;
3) n (Fe) = n (Cl2) * 2/3 = 0.15 * 2/3 = 0.1 mol;
4) m (Fe) = n (Fe) * M (Fe) = 0.1 * 56 = 5.6 g;
5) n (FeCl3) = n (Cl2) * 2/3 = 0.15 * 2/3 = 0.1 mol;
6) Mr (FeCl3) = Ar (Fe) * N (Fe) + Ar (Cl) * N (Cl) = 56 * 1 + 35.5 * 3 = 162.5;
7) ω (Fe in FeCl3) = N (Fe in FFeCl3Cl3) * Ar (Fe) * 100% / Mr (FeCl3) = 1 * 56 * 100% / 162.5 = 34.46%;
8) ω (Cl in FeCl3) = 100% – ω (Fe in FeCl3) = 100% – 34.46% = 65.54%.

Answer: The amount of Fe is 0.1 mol; weight – 5.6 g; the amount of the substance FeCl3 – 0.1 mol; mass fraction of Fe – 34.46%; Cl – 65.54%.