How much is a 0.6 m3 concrete slab lighter in salt sea water than in air?

To find out the change in the weight of the specified concrete slab in sea water, we use the formula: FА = ΔР = ρmw * g * V.

Const: ρmv – density of seawater (according to the condition of the principle ρmv = 1.03 * 10 ^ 3 kg / m3); g – acceleration due to gravity (g ≈ 10 m / s2).

Data: V – slab volume (V = 0.6 m3).

Let’s make a calculation: ΔР = ρmv * g * V = 1.03 * 10 ^ 3 * 10 * 0.6 = 6.18 * 10 ^ 3 N.

Answer: The specified concrete slab in sea water will become lighter by 6.18 kN.