How much is required to heat 205 g of water by 5 C?
| April 2, 2021 | education
m = 205 g = 0.205 kg.
Δt = 5 ° C.
C = 4200 J / kg * ° C.
Q -?
The amount of thermal energy required for heating water is expressed by the formula: Q = C * m * Δt, where C is the specific heat capacity of water, m is the mass of heated water, Δt is the change in water temperature during heating.
We take the specific heat capacity of water from the table of specific heat capacity of substances: C = 4200 J / kg * ° C.
Substitute the data into the formula: Q = 4200 J / kg * ° C * 0.205 kg * 5 ° C = 4305 J.
Answer: to heat water, you need Q = 4305 J of thermal energy.
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