How much is the internal energy of water vapor with a mass of 0.3 g, taken at a temperature of 100 degrees

How much is the internal energy of water vapor with a mass of 0.3 g, taken at a temperature of 100 degrees, more than the internal energy of the same mass of water taken at a temperature of 20 degrees?

Given:
mv.p. = 0.3 * -10 ^ -3g
t = 100 °
mw. = 0.3g
t = 20 °
M = 18 * 10 ^ -3g
R = 8.31
T2 = 373
T1 = 293
Compare:
U1 and U2
Decision:
U1 = 3/2 * m.p. / M * R * T2
U2 = 3/2 * mv. / M * R * T1
U2-U1 = 3/2 * 0.3 * 10 ^ -3 / 18 * 10 ^ -3 * 8.31 * (373-293) = 16.62J
Answer: 16.62J