How much is the mass of gold with a volume of 1 m3 greater than the mass of lead of the same volume?
| August 6, 2021 | education
Since both gold and lead occupy the same volume of 1 m ^ 3, the difference in their masses will be equal to the difference in their densities, taken in accordance with the dimension kg / m ^ 3.
Gold: ρz = 19,300 kg / m ^ 3.
Lead: ρс = 11 300 kg / m ^ 3.
Since ρz <ρс, gold will have a greater mass.
How much more is the mass of gold: ρз – ρс = 19,300 – 11,300 = 8,000 kg or 8 tons.
Answer: The mass of 1 m ^ 3 of gold will be 8,000 kilograms (8 tons) more.
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