How much is the spring with a stiffness of 100 N / m lengthened if the elastic force is 20 N?
| June 21, 2021 | education
Initial data: k (spring rate); Fel (value of the elastic force during spring deformation) = 20 N.
The amount of elongation of the spring can be determined using Hooke’s law: Fcont = | k * Δl |, whence Δl = Fcont / k.
Let’s calculate the elongation of the spring: Δl = 20/100 = 0.2 m (20 cm).
Answer: The spring has lengthened by 20 centimeters.
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