To calculate the desired mass of consumed kerosene, we use the equality (we do not take into account the loss of thermal energy): λ * ml = qk * mk, whence we express: mk = λ * ml / qk.
Constants and variables: λ – specific heat of melting of ice (λ = 3.4 * 10 ^ 5 J / kg); ml is the mass of molten ice (ml = 8 kg); qк – specific heat of combustion of kerosene (qк = 4.6 * 10 ^ 7 J / kg).
Calculation: mk = λ * ml / qk = 3.4 * 10 ^ 5 * 8 / (4.6 * 10 ^ 7) ≈ 0.06 kg.
Answer: It is necessary to burn 0.06 kg (60 g) of kerosene.
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