How much kerosene was burned if 688 MJ was released?

1) Let’s calculate the mass of the burnt kerosene.

Q = q * m, where Q is the energy released during the combustion of kerosene (Q = 688 MJ = 688 * 10 ^ 6 J), q is the specific heat of combustion (for kerosene we take q = 4.6 * 10 ^ 7 J / kg) , m is the mass of burnt kerosene.

m = Q / q = 688 * 10 ^ 6 / 4.6 * 10 ^ 7 = 14.96 kg.

2) Calculate the volume of kerosene burned:

V = m / ρ, where ρ is the density (for kerosene ρ = 810 kg / m3).

V = m / ρ = 14.96 / 810 = 0.018 m3.

Answer: 0.018 m3 of kerosene was burned.