How much lead did Stas melt if, after heating the lead to the melting temperature, 2400 J

How much lead did Stas melt if, after heating the lead to the melting temperature, 2400 J of heat was spent on it? (Lamba is equal to 24300)

Initial data: Q (consumed amount of heat for melting lead) = 2400 J.

Reference values: according to the condition λ (specific heat of fusion of lead) = 24300 J / kg.

The mass of lead that Stas was able to melt is determined by the formula: m = Q / λ.

Calculation: m = 2400/24300 = 0.0988 kg (98.8 g).

Answer: Stas was able to melt 98.8 grams of lead.



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