How much limestone is needed to extract 1.12 liters of CO2?

univerkov | May 10, 2021 | education

1. Let’s write down the reaction equation:

CaCO3 = CaO + CO2.

2. Find the amount of carbon dioxide (Vm – molar volume, constant equal to 22.4 l / mol):

n (CO2) = V (CO2) / Vm = 1.12 l / 22.4 l / mol = 0.05 mol.

3. According to the reaction equation, we find the amount and then the mass of calcium carbonate:

n (CaCO3) = n (CO2) = 0.05 mol.

m (CaCO3) = n (CaCO3) * M (CaCO3) = 0.05 mol * 100 g / mol = 5 g.

Answer: m (CaCO3) = 5 g.

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