How much m3 is contained in 45.75 kg of chlorine (VII) oxide?

univerkov | May 3, 2021 | education

Decision:
V = n * Vm n = m / M
n (CI₂O₇) = 45750/183 = 250 mol. V = 250 * 22.4 = 5600 l = 5.600 m3
Answer: 5,600 m3

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