How much m3 is contained in 45.75 kg of chlorine (VII) oxide?

univerkov | May 3, 2021 | education

Given:
m (Cl2O7) = 45.75 kg
Find: V

Decision:
V = n * Vm
n = m / M
n (Cl2O7) = 45750/183 = 250 mol.
V = 250 * 22.4 = 5600 l = 5.6 m3

Answer: 5.6 m3

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