How much magnesium can react with a solution containing 19.8 g of sulfuric acid?

How much magnesium can react with a solution containing 19.8 g of sulfuric acid? The reaction products are magnesium sulfate and hydrogen.

Magnesium dissolves in sulfuric acid solution. The reaction is described by the following chemical equation:

Mg + H2SO4 = MgSO4 + H2 ↑;

Let’s determine the chemical amount of sulfuric acid.

For this purpose, we divide its weight by the weight of 1 mole of acid.

M H2SO4 = 2 + 32 + 16 x 4 = 98 grams / mol;

N H2SO4 = 19.8 / 98 = 0.202 mol;

The same amount of magnesium will react.

Let’s calculate its mass.

To do this, we multiply the molar amount of the substance by the weight of 1 mole of metallic magnesium.

M Mg = 24 grams / mol;

m Mg = 0.202 x 24 = 4.849 grams;