How much magnesium is required to interact with 292 g of 15% hydrochloric acid solution?

Mg + 2HCl = MgCl2

Let’s find the mass and amount of pure hydrochloric acid substance:

m (HCl) = m (solution) * w (HCl) = 292 * 0.15 = 43.8 g;

n (HCl) = m (HCl): M (HCl) = 43.8 / 36.5 = 1.2 mol;

According to the stoichiometry of the reaction:

n (Mg) = 0.5n (HCl) = 1.2 * 0.5 = 0.6 mol;

Let’s find the mass of magnesium:

m (Mg) = n (Mg) * M (Mg) = 0.6 * 24 = 14.4 g.

Answer: m (Mg) = 14.4 g.