How much magnesium oxide will be obtained by firing 8.4 kg of magnesium carbonate

How much magnesium oxide will be obtained by firing 8.4 kg of magnesium carbonate if the mass fraction of the output of mgo is 80% of the theoretically possible.

To solve the problem, we compose the equation of the process:

1.MgCO3 = MgO + CO2 – decomposition, formed magnesium oxide, carbon dioxide;

Calculations according to the formulas of substances:
M (MgCO3) = 84.9 g / mol;

M (MgO) = 40.9 g / mol;

Y (MgCO3) = m / M = 8400 / 84.9 = 98.9 mol.

3. Find the mass of the product:

m (MgCO3) = Y * M = 98.9 * 40.9 = 4045 g (theoretical weight);

m (MgCO3) = 0.80 * 4045 = 3236 g (practical weight).

Answer: obtained magnesium oxide weighing 3 kg 236 g