How much magnesium will react with sulfate acid weighing 49 g?
| December 8, 2020 | education
m (H2SO4) = 49 grams
n (Mg) -?
M (H2SO4) = 98 grams / mol
n (H2SO4) = m (H2SO4) / M (H2SO4) = 49 grams / 98 grams / mol = 0.5 mol
Mg + H2SO4 = MgSO4 + H2 ↑
From the stoichiometric coefficients of the reaction equation it follows that: n (Mg) = n (H2SO4) = 0.5 mol
Answer: 0.5 mol of magnesium will react.
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