How much mass of hydrogen is required to convert 160 g of copper oxide to pure copper?

Copper oxide is reduced with hydrogen gas. This synthesizes metallic copper and water. This reaction is described by the following equation:

CuO + H2 = Cu + H2O;

Copper oxide reacts with hydrogen in equal molar amounts. At the same time, the same equal amounts of copper and water are synthesized.

Let’s calculate the chemical amount of copper.

To do this, divide the weight of the metal oxide by the weight of 1 mole of this metal oxide.

M CuO = 64 + 16 = 80 grams / mol;

N CuO = 160/80 = 2 mol;

Thus, 2 mol of copper oxide can be reduced and 2 mol of copper can be synthesized.

Let’s calculate the mass and volume of 2 mol of hydrogen.

M H2 = 2 grams / mol;

m H2 = 2 x 2 = 4 grams;

V H2 = 2 x 22.4 = 44.8 liters;