How much memory is required to store sound information with a sounding time of 3 minutes

How much memory is required to store sound information with a sounding time of 3 minutes with a sampling rate of 44.01 kHz and a coding depth of 16 bits, which sound time is 3 minutes.

Since 3 minutes = 3 * 60 = 180 s, the total number of sample-storage operations will be:

180 * 44010 = 7921800.

Since 16 bits of information occupy 2 bytes in memory, the total amount of required memory will be equal to:

2 * 7921800 = 15843600 bytes = 15.1 MB.



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