How much mercury oxide is required to produce 12.8 g of oxygen?

In this task, you will need to determine the mass of mercury oxide.

First, you need to draw up the equations of chemical reactions.

2HgO = 2Hg + O2.

Let’s determine the amount of oxygen. For this we use the following formula.

n = m / M.

Let’s define the molar mass of oxygen.

M (O2) = 32 g / mol.

n (O2) = 12.8 / 32 = 0.4 mol.

Let’s make a proportion.

X mol – 0.4 mol.

2 mol – 1 mol.

X = 2 * 0.4 / 1 = 0.8 mol of mercury oxide.

Determine the mass of mercury oxide.

M (HgO) = 217 g / mol.

m (HgO) = n * M = 217 * 0.8 = 173.6 g.

This means that the mass of mercury oxide is 173.6 g.

Answer: 173.6 g.