How much methane can be burned in 24 liters of oxygen?
| August 7, 2021 | education
The methane oxidation reaction is described by the following chemical reaction equation.
CH4 + 2O2 = CO2 + 2H2O;
According to the coefficients of this equation, the oxidation of 1 methane molecule requires 2 oxygen molecules. This synthesizes 1 molecule of carbon dioxide.
The molar volume of the gas is standard and fills a volume of 22.4 liters under normal conditions.
Since the molar volume of the gas is standard, twice the amount of oxygen will require half its volume of methane:
The required volume of methane is 24/2 = 12 liters.
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