How much methane can be burned using 112 L oxygen?

Methane completely burns out in sufficient oxygen to form carbon dioxide and water. With a lack of oxygen, the reaction products can be different. But since these conditions are not specified in the problem statement; let us take complete combustion.

The equation can be written as follows:

CH4 + 2 O2 = CO2 + 2 H2O

The molar mass of methane is 16 g / mol; the molar volume of oxygen is 22.4 l / mol (according to Avogadro’s law).

Let’s compose the proportion according to the chemical reaction equation:

X g of methane corresponds to 112 liters. oxygen like

16 g / mol of methane corresponds to 2 * 22.4 l / mol of oxygen

X = (112 * 16) / (2 * 22.4) = 40 g of methane

Answer: the mass of methane is 40 g.