How much methane can be obtained by hydrolysis of 28.8 g of aluminum carbide?

Based on the condition of the problem, we compose the equation for the hydrolysis of aluminum carbide:
Al4C3 + 12H2O = 3CH4 + 4Al (OH) 3 – methane is released;

Calculations by formulas:
M (Al4C3) = 143.6 g / mol;

Y (Al4C3) = m / M = 28.8 / 143.6 = 0.2 mol.

Proportion:
0.2 mol (Al4C3) – X mol (CH4);

-1 mol -3 mol from here, X mol (CH4) = 0.2 * 3/1 = 0.6 mol.

Find the volume of the product:
V (CH4) = 0.6 * 22.4 = 13.44 L

Answer: methane produced with a volume of 13.44 liters