How much natural gas is required to heat 200 g of water at 100 degrees?

How much natural gas is required to heat 200 g of water at 100 degrees? (Specific heat capacity of water 4200 J / kg * degrees, specific heat of combustion of natural gas 4.4 * 10 ^ 7 J / kg)

Using the law of conservation of energy, we obtain the equation for the energy balance of the system:

m1 * C * T = Q * m2, where m1 is the mass of water, T is the temperature difference, m2 is the mass of natural gas, C is the specific heat capacity of water, Q is the specific heat of combustion of gas. Let us express m2 from this formula:

m2 = m1 * C * T / Q.

We substitute the known values into the resulting formula:

m2 = 0.2 * 4200 * 100 / 4.4 * 10 ^ (7) = 1.9 * 10 ^ (- 3) kg = 1.9 g.

Answer: the required amount of gas is 1.9 g.