How much nitrogen is theoretically formed when 20 liters of ammonia are oxidized?

Given:
V (NH3) = 20 l
Find: V (N2) -?
Decision:
1) Write the equation of a chemical reaction:
4NH3 + 3O2 => 6H2O + 2N2;
2) According to the Gay-Lussac law (the law of volumetric ratios), it is necessary to make a proportion and solve it:
4 l NH3 – 2 l N2;
20 l NH3 – x l N2;
V (N2) = x = 20 * 2/4 = 10 liters.
Answer: The volume of N2 formed is 10 liters.



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