How much nitrogen oxide (||) by weight and volume can be obtained by dissolving 6.4 g

How much nitrogen oxide (||) by weight and volume can be obtained by dissolving 6.4 g of copper in nitrous acid (HNO2).

Given:
m (Cu) = 6.4g
To find:
m (NO) -?
V (NO) -?

The reaction equation is:
Cu + 8HNO2 = Cu (NO3) 2 + 6NO + 4H2O
Let’s write an expression to determine the amount of a substance:
ν = m / M = V / Vm
Determine the amount of copper substance:
M (Cu) = 64g / mol
ν (Cu) = m (Cu) / M (Cu) = 6.4 / 64 = 0.1 mol.
Determine the amount of nitrogen oxide substance, according to the reaction equation:
ν (NO) = 6 * ν (Cu) = 6 * 0.1 = 0.6 mol.
Let us find the volume of the gas, taking into account that Vm (NO) = 22.4 l / mol:
V (NO) = ν (NO) * Vm (NO) = 0.6 * 22.4 = 13.44 liters.
Now let’s determine the mass of the gas:
M (NO) = 14 + 16 = 30g / mol
m (NO) = ν (NO) * M (NO) = 0.6 * 30 = 18 g.
Answer: the mass of nitric oxide is 18 g, and the volume is 13.44 liters.



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