How much of a substance is contained in 4.5 g of nitric oxide (2)?

univerkov | August 23, 2021 | education

Given:
m (NO) = 4.5 g

Find:
n (NO) -?

1) M (NO) = Mr (NO) = Ar (N) * N (N) + Ar (O) * N (O) = 14 * 1 + 16 * 1 = 30 g / mol;
2) n (NO) = m (NO) / M (NO) = 4.5 / 30 = 0.15 mol.

Answer: The amount of the substance NO is 0.15 mol.

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