How much oil is delivered in one hour through a pipeline with a diameter of 0.50 m at an oil speed of 1.0 m / s?

To find the mass of the delivered oil, we will use the formula: m = ρн * V = ρн * S * h = ρн * (0.25 * Π * d ^ 2) * (Vн * t).

Constants and variables: ρн – oil density (ρн = 835 kg / m3); d – pipeline diameter (d = 0.5 m); Vн – speed of oil movement (Vн = 1 m / s); t is the time of oil movement (t = 1 h = 3600 s).

Let’s perform the calculation: m = ρn * 0.25 * Π * d ^ 2 * Vn * t = 835 * 0.25 * 3.14 * 0.52 * 1 * 3600 = 589927.5 kg ≈ 590 tons.

Answer: In 1 hour, 590 tons of oil will be delivered via the pipeline.