How much oxygen do you need to take to oxidize 1 liter of sulfur (IV) oxide?

univerkov | May 13, 2021 | education

The oxidation process of sulfur (IV) oxide produces sulfur (VI) oxide.

The reaction equation is: 2SO2 + O2 = 2SO3.

Based on the reaction equation, we will compose the proportion.

For oxidation of 44.8 l / mol of oxide, 22.4 l / mol of oxygen is needed.

To oxidize 1 liter of oxide, you need x liters of oxygen.

x = 22.4 * 1 / 44.8 = 0.5 l.

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