How much oxygen in liters is required to burn 11.2 liters of nitrogen to nitric oxide (II).

Let’s write the reaction equation:

N2 + O2 (t) = 2NO

Amount of nitrogen substance:

v (N2) = V (N2) / Vm = 11.2 / 22.4 = 0.5 (mol).

According to the reaction equation, 1 mol of N2 interacts with 1 mol of O2, therefore:

v (O2) = v (N2) = 0.5 (mol).

Thus, the required volume of oxygen, measured under normal conditions (n.o.):

V (O2) = v (O2) * Vm = 0.5 * 22.4 = 11.2 (l).

Answer: 11.2 l.