How much oxygen is consumed for the combustion of CH4 with a volume of 100 liters?

1. We make the equation of a chemical reaction.
CH4 + 2O2 → CO2 + 2H2O

2. We calculate the amount of methane.

n (CH4) = V (CH4): Vm = 100: 22.4 L / mol = 4.46 mol.

3. The reaction equation shows that 1 mol of methane CH4 reacts with 2 mol of oxygen. This means that 4.46 moles of methane CH4 interact with 4.46 × 2 = 8.92 moles of oxygen.

4. Let’s calculate the volume of oxygen.

V (O2) = n (O2) × Vm = 8.92 mol × 22.4 L / mol = 199.8 L.

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